Conic sections The lines 2x 3y 5 and 3x 4y 7 are diameters of The lines 2x− 3y = 5 2 x − 3 y = 5 and 3x − 4y = 7 3 x − 4 y = 7 are diameters of a circle of area 154 sq unitis Then, the equation of this circle is JEE Advanced 19 x2 y2 2x−2y= 62 x 2 y 2 2 x − 2 y = 62 x2 y2 2x−2y= 47 x 2 y 2 2 x − 2 y = 47 всего ответов 2 на вопрос 2x3y=143x2y=8 на iznaniyacom Explanation Move the x term to the right side, then divide everything by 3 2x 3y = 3 3y 2x = 3 3y 2x − 2x = 3 −2x 3y 2x −2x = 3 − 2x 3y =

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Answery= −2/3x2Stepbystep explanation2x3y=6Add 2x to both sides2x3y−2x=6−2x3y=−2x6 Divide both sides by 33y/3=−2x6/3 wereddiyougo wereddiyougoSee all questions in Expressions and the Distributive PropertyAnswer (1 of 11) Let me show you the algebra here real quick and then I'll explain in more detail (2x3y)^2=(3x2y)^2 (2x3y) = (3x2y);



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Studied at University of Bologna,Italy Author has 19K answers and 8495K answer views 1 y The equation can be rewritten as dy/dx (3/2)y/x = y^3/ (2x^3) which is a Bernoulli equation Taking y = V (x)^ (1/2 ) obtain the equation in normal form V' 3V/x = 1/x^3 The two equations, therefore are just two different representations of the same line graph {2x3y=21 228, 228, 114, 1142} Algebraically we can see it this way Take 2x − 3y = 21 (2 3)x − y = 21 3 = 7 (Divide each term with 3) y = ( 2 3)x −7 (subtract y7 from both sides) We see that the second equation is converted to the firstFactor 2x^2xy3y^2 2x2 xy − 3y2 2 x 2 x y 3 y 2 Factor by grouping Tap for more steps For a polynomial of the form a x 2 b x c a x 2 b x c, rewrite the middle term as a sum of two terms whose product is a ⋅ c = 2 ⋅ − 3 = − 6 a ⋅ c = 2 ⋅ 3 = 6 and whose sum is b = 1 b = 1 Tap for more steps Reorder terms




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Answer (1 of 3) \\ 2x^3 \cdot y' = y \cdot (y^23x^2) \implies 2x^3 \cdot \dfrac{\mathrm dy}{\mathrm dx} = y^3 3x^2y \implies 2x^3 \cdot \mathrm dy = y^3 \cdot \mathrm dx 3x^2y \cdot \mathrm dx \tag{E01} \text{Let } y = vx \implies \mathrm dy(2x3y) = 1(3x 2yFree PreAlgebra, Algebra, Trigonometry, Calculus, Geometry, Statistics and Chemistry calculators stepbystep



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Free PreAlgebra, Algebra, Trigonometry, Calculus, Geometry, Statistics and Chemistry calculators stepbystep Use the product and quotients rules and do a lot of tedious algebra to get #dy/dx=(3x^42x^3yy^2)/(2xyx^4)#Nilai minimum fungsi objektif z 3x 5y yang memenuhi 2x y ≥ 8 2x 3y ≥ 12 x ≥ 0;




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Systemofequationscalculator 2x 3y = 9, y = x 2 en image/svgxml Related Symbolab blog posts High School Math Solutions – Systems of Equations Calculator, Elimination A system of equations is a collection of two or more equations withGraph and solve the system 3x 4y < 12 x 3y < 6 Explanation Bring these inequalities to standard form (1) 3x 4y 12 < 0 (2) x 3y 6 < 0 First, graph the line 3x 4y 12 = 0 by its 2 How do you solve \displaystyle{x}{3}{y}={1} and \displaystyle{3}{x}{3}{y}={15} The method to solve such differential equations is Substitute x 2 = u 2 x d x = d u and y 2 = v 2 y d y = d v Then it's neat, a dy/dx = linear/linear type equation is obtained which can be solved using standard techniques of y = Y k and x = X h to eliminate the constant terms from both the linears Share




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See the answer See the answer See the answer done loading 2x^3y' = y(y^2 3x^2) find the general solution Expert Answer Who are the experts? color(red)( x=5,y=12) > One way is to use the method of elimination Step 1 Enter the equations 1 3xy=3 2 2xy=2 Step 2 Add the equations 3 x=5 Step 3 Substitute Equation 3 in Equation 2 2xy=2 2(5)y=2 10y =2 y=12 Solution x=5,y=12 Check Substitute the values of x and y in Equation 1 3xy=3 3(5)12=3 1512=3 3=3Hgrilliot7 Hgrilliot7 Mathematics High School answered Y=2/3x3,2x3y=8 determine whether perpendicular or parallel 1 See answer Advertisement



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Trigonometry Examples Popular Problems Trigonometry Graph y=2x^23x2 y = 2x2 − 3x − 2 y = 2 x 2 3 x 2 Find the properties of the given parabola Tap for more steps Rewrite the equation in vertex form Tap for more stepsTo find the xintercept (s), substitute in 0 0 for y y and solve for x x 0 = − 2 x 3 2 0 = 2 x 3 2 Solve the equation Tap for more steps Rewrite the equation as − 2 x 3 2 = 0 2 x 3 2 = 0 − 2 x 3 2 = 0 2 x 3 2 = 0 Subtract 2 2 from both sides of the equation − 2 x 3 = − 2 2 x 3 = 2Xy = 2x^2/3 5y^2/3 Set these eq equal and solve X^2y^2=0 Or x^2=Y^2 Or x=y Graph is straight line x=y To prove (0,0) is a saddle point of f (x,y)=x^22xyy^2x^3y^3x^5 To prove (0,0) is a saddle point of f (x,y)= x2 − 2xy y2 x3 − y3 x5




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Rewrite using the commutative property of multiplication 2 ⋅ 3 ( x ⋅ x 2) 2 x y y ( 3 x 2) y ⋅ y 2 ⋅ 3 ( x ⋅ x 2) 2 x y y ( 3 x 2) y ⋅ y Multiply x x by x 2 x 2 by adding the exponents Tap for more steps Multiply x x by x 2 x 2 Tap for more steps Raise x x to the power of 1 1Factor 3x^22xyy^2 3x2 2xy − y2 3 x 2 2 x y y 2 Factor by grouping Tap for more steps For a polynomial of the form a x 2 b x c a x 2 b x c, rewrite the middle term as a sum of two terms whose product is a ⋅ c = 3 ⋅ − 1 = − 3 a ⋅ c = 3 ⋅ 1 = 3 and whose sum is b = 2 b = 2 Tap for more steps Reorder terms



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